A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Nov 25, 2013 · Such declaration are really used !. Consider the signal function of the standard C library: void (* signal(int sig, void (*func)(int)))(int); the signal man page explains it is equivalent …

Sep 25, 2010 · int** i (Ie, in the second case you will require two dereferrences to access the integer's value)

int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process …

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

64 I prefer int* i because i has the type "pointer to an int", and I feel this makes it uniform with the type system. Of course, the well-known behavior comes in, when trying to define multiple …

In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given. Are the two really the same? Is there a reason …

Aug 3, 2008 · In Java, the 'int' type is a primitive, whereas the 'Integer' type is an object. In C#, the 'int' type is the same as System.Int32 and is a value type (ie more like the java 'int'). An integer …

int is a primitive data type while Integer is a Reference or Wrapper Type (Class) in Java. after java 1.5 which introduce the concept of autoboxing and unboxing you can initialize both int or …

I saw someone using this in one answer: void methodA(const int*& var); I couldn't understand what the argument means. AFAIK: const int var => const int value which can't …